The length of a rectangle is 8ft greater than it's width. If the width were doubled, the area of the rectangle would be 84 sq. ft. greater than it is now. Find the dimensions of th

• length be l and breadth be b
  a/q
  l=b+8
  & 2l(l-8)-l(l-8)=84
  =>l=14 hence b=6
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