On average age something like a, b, c weighted separately 1st a, b, c, then a & b, then b
&c , then c 7 a at last abc, then last weight was 167, then what will be the avg. weight of the 7
weight?

• a+b+c = 167
  7 weights are
  a+b+c+(a+b)+(b+c)+(a+c) +(a+b+c) = 4*(a+b+c) = 4*167= 668
  Average of 7 weights = 668/7 = 95.43 units
• 13 years agoHelpfull: Yes(12) No(0)
• ITS GIVEN:
  A+B+C=167
  NOW,
  7 WEIGHTS ARE:
  A+B+C+(A+B)+(B+C)+(C+A)+(A+B+C)=4*(A+B+C)=4*167=668
  NOW,AVG WEIGHT=668/7=95.428
  
• 13 years agoHelpfull: Yes(5) No(1)
• a+b+c = 167
  7 weights are
  a+b+c+(a+b)+(b+c)+(a+c) +(a+b+c) = 3*(a+b+c) = 3*167= 501
  
  Average of 7 weights = 501/7 = 71.57 units
• 13 years agoHelpfull: Yes(3) No(11)
• 
  a+b+c = 167
  7 weights are
  a+b+c+(a+b)+(b+c)+(a+c) +(a+b+c) = 3*(a+b+c) = 3*167= 501
• 13 years agoHelpfull: Yes(2) No(6)