Product of two consecutive integers is 4290.find such integers

• Let d 2 consecutive integers be x, x+1
  x * (x+1) = 4290
  x^2 + x - 4290 = 0
  x = -66, 65
  Take +ve no => x=65
  So the consecutive no's are 65, 66
  
  Ans : 65 , 66
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• 2*3*5*11*13=4290
  so we take 2*3*11=66 and 5*13=65
  so answer 65,66
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• 65,66 and -65,-66 :)
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• 65,66
  
  Let the numbers be x and (x+1)
  
  x(x+1) = 4290
  x^2 - x -4290 = 0
  
  x = -1(+-)sqrt(1+4*4290)/2
  =-1(+-)131/2
  =130/2
  =65
  
  The numbers are 65,66
  
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