There are 4 boys and 3 girls seated in a row.Find the probability that all girls are together?

• Total No. of ways boys and girls can be seated = (4 + 3)! = 7! = 5040
  No. of ways that girls seated together =>
  consider 3 girls as a unit nd remaining 4 boys can be seated in any order...
  So (1 + 4)! = 5! = 120
  And those 3 girls can be seated among themselves in 3! ways => 6
  
  [(ie) Let g1,g2,g3 be the girls... in 6 ways they can be seated together...
  g1g2g3, g1g3g2, g2g1g3, g2g3g1, g3g1g2, g3g2g1]
  
  So prob. that all girls are together => (120 * 6)/5040 => 1/7
  
  Ans : 1/7
• 10 years agoHelpfull: Yes(17) No(1)
• ((4+1)!)(3!)
• 10 years agoHelpfull: Yes(1) No(0)
• 7!
  (4+1)!=120
  120/7!
  120/5040
  1/42
• 10 years agoHelpfull: Yes(1) No(1)
• Number of ways boys and girls can be seated = (4+3)! = 7!
  Number of ways boys and girls can be seated with girls sitting together = (4+1)! = 5!
  
  Probability that girls are together = 5!/7!
  =1/42
  
• 10 years agoHelpfull: Yes(0) No(1)