General
Maths Puzzle
Numerical Ability
Number System
a certain number when divided by 134 leaves a remainder 25, another number when divided by 312 leaves a remainder 53 . what is the remainder when the sum of these two numbers is divided by 33
Read Solution (Total 4)
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- if we multiply the 134 by 1 & then adding the remainder 25,it gives 159.i.e.,134*1+25=159
in the same way if we do for the 2nd no. it gives 365.i.e.,312*1=53=365
now,159+365=524
divide 524 by 33 then remainder is 29 - 10 years agoHelpfull: Yes(1) No(0)
- here we multiple by 5 and add reminder
so
suppose first no is 134*5+25=695
second no is 312*5+53=1613
addition of these 2 no= 2308
now we divided by 33 then reminder is 31 - 10 years agoHelpfull: Yes(0) No(4)
- @ SHREE , y should we multiply only 5 , let it be 1 r 2 r 3 ..... different answers r coming for different quotients .
- 10 years agoHelpfull: Yes(0) No(2)
- I think some condition is missing in given statement.
With given statement, there can be multiple solutions.
no unique solution. - 10 years agoHelpfull: Yes(0) No(0)
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