What is the output of:
#include
int main()
{
int x=40;
{
int x=20;
printf("%d",x);
}
printf("%d",x);
return 0;
}

• Output : 20, 40
  
  x = 20 is declared inside a block...
  so that can be accessed in that block only...
  Outside that block x = 40...
  
• 10 years agoHelpfull: Yes(14) No(1)
• INT X=40, IS A GLOBAL DECLARATION BUT AS LOCAL VARIABLE HAS HIGHER PRECEDENCE THAN
  GLOBAL,THEREFORE X=20,X=40 WHICH IS GLOBAL......
• 10 years agoHelpfull: Yes(3) No(0)
• 20
  40
  first the local variable x will be printed followed by global variable x
• 5 years agoHelpfull: Yes(0) No(0)
• 20 40
  20 is in braket so it will get printed first .after that 40.
• 4 years agoHelpfull: Yes(0) No(0)
• 40 20 scope of their brackets
• 3 years agoHelpfull: Yes(0) No(1)
• 20 will ne the output
• 2 years agoHelpfull: Yes(0) No(0)
• Output :20 ,40
• 1 year agoHelpfull: Yes(0) No(0)
• it shows error: header file not there
• 1 year agoHelpfull: Yes(0) No(0)
• answer is 2040
• 6 Months agoHelpfull: Yes(0) No(0)