What is the output of the following program?
#include
int main(){
double d=5.2;
int i=5;
printf("%dt",sizeof(!d));
printf("%dt",sizeof(i=15/2));
printf("%d",i);
return 0;
}

• Output : 2 2 5
  
  sizeof(!d) => sizeof(!5.2) => sizeof(0) => sizeof(int) = 2 [since 0 is an integer]
  sizeof(i=15/2) => sizeof(i=7)=> sizeof(int) = 2 [since i is an integer, it ll store only the integer part of 15/2 = 7]
  next it ll print the i value of 5
  
  So o/p is 2 2 5
  
• 10 years agoHelpfull: Yes(20) No(0)
• Output : 4t4t5
  checked on dev c++
• 10 years agoHelpfull: Yes(3) No(0)
• Answer: 2 2 5
  
  sizeof(!d) => sizeof(!5.2) => sizeof(int) = 2 [since 0 is an integer]
  sizeof(i=15/2) => sizeof(i=7)=> sizeof(int) = 2
  i value of 5
  
  So Answer is is 2 2 5
• 10 years agoHelpfull: Yes(2) No(0)
• o/p=2t2t5
  inside sizeof() no operation get evaluated.........
  that why i value will remain same.
  
• 10 years agoHelpfull: Yes(2) No(0)
• Output : 2t2t5
  
  sizeof(!d) => sizeof(!5.2) => sizeof(0) => sizeof(int) = 2 [since 0 is an integer]
  sizeof(i=15/2) => sizeof(i=7)=> sizeof(int) = 2 [since i is an integer, it ll store only the integer part of 15/2 = 7]
  next it ll print the i value of 5
  
  So o/p is 2t2t5
• 10 years agoHelpfull: Yes(1) No(0)
• 2 2 7
  ...........
• 10 years agoHelpfull: Yes(0) No(2)
• 4 4 5
  double=4
  int in unix system =4
  and i=5
• 10 years agoHelpfull: Yes(0) No(0)
• 2 2 5
  here sizeof(i=15/2) here i scope will be within the size of opeartor outside i will be agin 5
• 10 years agoHelpfull: Yes(0) No(0)
• 445
  because the ! converts it into int..and the rest is obvious
  
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• Output : 2 2 5
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• 2t2t5 OR 4t4t5
  depends on compiler
• 5 years agoHelpfull: Yes(0) No(0)
• its output will be 4t4t5
  because sizeof(!5.2)= sizeof(0)=sizeof(int)=4 and also 't' because only %d is format specifier and t is like a string. similarly sizeof(i=15/2)=sizeof(i=7) here 15/2 is 7 because i is int so sizeof(int)=4 and also t.
  & printf("%d",i)=5 because sizeof operator not changes original value of i
• 5 years agoHelpfull: Yes(0) No(0)
• output: 1t4t5
• 5 years agoHelpfull: Yes(0) No(0)