What is the output of:
#include
void main( )
{
printf ( "nn nn nnn" ) ;
printf ( "nn /n/n nn/n" ) ;
}

• Output : nn nn nnnnn /n/n nn/n
  
  n ll provide a new line... But /n ll print the same /n in the o/p screen...
• 10 years agoHelpfull: Yes(34) No(8)
• nothing will be changed....it will print same as in printf
  nn nn nnn nn /n/n nn/n
  because it is a forward slash(/) and newline character is like this(n)....
• 9 years agoHelpfull: Yes(4) No(2)
• /n wil provide a new line in dis.. so oput wil b:
  nn nn nnn
  nn
  
  nn
• 9 years agoHelpfull: Yes(3) No(21)
• nn nn nnnnn /n/n nn/n because n provides a new lie and not /n.So otput will be in the same line.
• 9 years agoHelpfull: Yes(3) No(3)
• output:
  nn nn nnnn /n/n nn/n
  
  because here they give forward slash(/), which does not change in output. If they give backward slash() then output will change
• 8 years agoHelpfull: Yes(3) No(0)
• nn nn nnnnn/n/n nn/n
• 9 years agoHelpfull: Yes(2) No(1)
• nn nn nnnnn /n/n nn/n
• 6 years agoHelpfull: Yes(2) No(0)
• nn nn nnnnn
  nn
• 9 years agoHelpfull: Yes(1) No(1)
• it will generate the error that bad file name format in include directive.
• 9 years agoHelpfull: Yes(1) No(0)
• nn nn nnnnn /n/n nn/n
• 8 years agoHelpfull: Yes(1) No(0)
• tell me right answer bcz widout cmplt first line ...cn it give output anyone tell me reason?????
• 9 years agoHelpfull: Yes(0) No(2)
• nn nn nnnnn
  n
  n nn
  n
• 9 years agoHelpfull: Yes(0) No(2)
• nn nn nnn
  nn
  /n
  nn
• 9 years agoHelpfull: Yes(0) No(2)
• o/P :
  nn nn nnn nn /n/n nn/n
  because (n) indicates the start of a new line and not forward slash n (n).
• 9 years agoHelpfull: Yes(0) No(1)
• it will be
  output: nn nn nnnnn /n/n nn/n
  
  
  because in c compiler new line code is n so it will print in ne line.
• 9 years agoHelpfull: Yes(0) No(0)
• The answer will be simply nn nn nnnnn /n/n nn/n all in the same line because its not a newline character the newline character is "n"
• 9 years agoHelpfull: Yes(0) No(0)
• nn nn nnn
  nn
  
  nn
  
• 9 years agoHelpfull: Yes(0) No(0)
• nn nn nnn nn nn
• 9 years agoHelpfull: Yes(0) No(0)
• /n is not used fr newline but the
  will generate a new line.so the output ll be
  nn nn nnn nn/n/n nn/n
• 9 years agoHelpfull: Yes(0) No(0)
• it will normally print as my other friend told above but there are some problem..
  if u run this program then it will not run on Dev c++ because "void main() function always want to return an integer"
  
  Is it run on any other compiler???
• 9 years agoHelpfull: Yes(0) No(0)
• There should be backward slash for new line.
• 9 years agoHelpfull: Yes(0) No(0)
• output is nn nn nnn
  nn
  
  
  nn
• 9 years agoHelpfull: Yes(0) No(0)
• nn nn nnnnn /n/n nn/n
  
• 9 years agoHelpfull: Yes(0) No(0)
• Output : nn nn nnnnn /n/n nn/n
  
  ie. printf scharacters will be printed as it is....
  
• 9 years agoHelpfull: Yes(0) No(0)
• nn nn nnn
  nn /n/n nn/n
  since in the to print in next line we use n escape sequence but here /n is used..
• 8 years agoHelpfull: Yes(0) No(0)
• nn nn nnn
  nn
  
  nn
• 7 years agoHelpfull: Yes(0) No(0)
• when we change void to int then it will print as it is in printf statements or it will provide declaration error
• 7 years agoHelpfull: Yes(0) No(0)
• output: nn nn nnnnn /n/n nn/n
  
  n - this one will print new line
  /n - not print a new line
  hope you understood this!
• 6 years agoHelpfull: Yes(0) No(0)
• nn nn nnnnn
  
  nn
• 6 years agoHelpfull: Yes(0) No(0)
• nn nn nnn
  nn
  
  nn
• 5 years agoHelpfull: Yes(0) No(0)
• It shoud be compile time error for just a simple reason that #include doesn't contains the header name,for which the printf function will remain unknown and beyond compiler understanding
• 5 years agoHelpfull: Yes(0) No(0)
• nn nn nnn nn
  
  nn
• 1 year agoHelpfull: Yes(0) No(0)
• nn nn nnn nn /n/n nn/n
• 1 year agoHelpfull: Yes(0) No(0)