Find the number of factors of 1728?
A. 18
B. 28
C. 30
D. 20

• B) 28
  
  if N = p^a * q^b *r^c *...
  then total no. of factors of N = (a+1)*(b+1)*(c+1)*...
  
  1728 = 2^6*3^3
  so, number of factors of 1728 = (6+1)*(3+1)= 28
  
• 10 years agoHelpfull: Yes(44) No(3)
• 1728=2^6*3^3
  No. of factors=(6+1)(3+1)=28
  option(b) is correct
• 10 years agoHelpfull: Yes(6) No(1)
• 2^6*3^3=1728;
  so 7*4=28;
  
• 10 years agoHelpfull: Yes(2) No(1)
• by factorization method
  we got 28 ans
  
• 9 years agoHelpfull: Yes(2) No(0)
• 2^6*3^3. (6+1)(3+1)=28
• 9 years agoHelpfull: Yes(2) No(0)
• ans:a
  1728 is divide by 18
• 10 years agoHelpfull: Yes(1) No(8)
• The prime factorization of 1728= 2^6 * 3^3
  so the number of factors is given by: (6+1)*(3+1)= 7*4 = 28
• 9 years agoHelpfull: Yes(1) No(0)
• @* Please decrypted and find solution ...
• 9 years agoHelpfull: Yes(0) No(1)
• 30 is answer will come by fertors
  
• 8 years agoHelpfull: Yes(0) No(4)