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Numerical Ability
LCM and HCF
Find the number of factors of 1728?
A. 18
B. 28
C. 30
D. 20
Read Solution (Total 9)
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- B) 28
if N = p^a * q^b *r^c *...
then total no. of factors of N = (a+1)*(b+1)*(c+1)*...
1728 = 2^6*3^3
so, number of factors of 1728 = (6+1)*(3+1)= 28
- 10 years agoHelpfull: Yes(44) No(3)
- 1728=2^6*3^3
No. of factors=(6+1)(3+1)=28
option(b) is correct - 10 years agoHelpfull: Yes(6) No(1)
- 2^6*3^3=1728;
so 7*4=28;
- 10 years agoHelpfull: Yes(2) No(1)
- by factorization method
we got 28 ans
- 10 years agoHelpfull: Yes(2) No(0)
- 2^6*3^3. (6+1)(3+1)=28
- 10 years agoHelpfull: Yes(2) No(0)
- ans:a
1728 is divide by 18 - 10 years agoHelpfull: Yes(1) No(8)
- The prime factorization of 1728= 2^6 * 3^3
so the number of factors is given by: (6+1)*(3+1)= 7*4 = 28 - 9 years agoHelpfull: Yes(1) No(0)
- @* Please decrypted and find solution ...
- 10 years agoHelpfull: Yes(0) No(1)
- 30 is answer will come by fertors
- 9 years agoHelpfull: Yes(0) No(4)
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