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Find the number of divisors of 1080 excluding the divisors which are perfect squares.
A. 28
B. 30
C. 29
D. 31
Read Solution (Total 8)
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- A) 28
1080 = 2^3 *3^3 *5^1
total no. of divisors = (3+1)*(3+1)*(1+1) = 32
only 4 divisors 1, 2^2=4 , 3^2=9 & 2^2*3^2=36 are perfect squares
so,number of divisors excluding perfect squares divisors = 32-4 = 28 - 10 years agoHelpfull: Yes(31) No(1)
- @Rakesh,@Rishabh
Hey..will u tell me how u calculated the no of divisors. - 10 years agoHelpfull: Yes(3) No(1)
- @vaishnavi
If a number can be written as N= a^p * b^q * c^r ......
where a,b,c are prime factors
then no.of divisors is ((p+1)*(q+1)*(r+1))
- 10 years agoHelpfull: Yes(3) No(1)
- 1080=2*2*2*3*3*5*1=2^3*3^2*5^1
total number of divisors=(3+1)*(3+1)*(1+1) = 32
now 32-4=28 - 10 years agoHelpfull: Yes(0) No(2)
- only 4 divisors 1, 2^2=4 , 3^2=9 & 2^2*3^2=36 are perfect squares
- 10 years agoHelpfull: Yes(0) No(0)
- 28,,, total no of divisor=32,divisor perfect square is 4 so which are not perfrect square is 28
- 9 years agoHelpfull: Yes(0) No(0)
- 1080=2^3*3^3*5^1
here total no of divisors=(3+1)(3+1)(1+1)=32
now perfect sqares are 2^2,3^2,(2.3)^2,excluding these......29 divisors remains - 9 years agoHelpfull: Yes(0) No(0)
- The answer is 28
- 4 years agoHelpfull: Yes(0) No(0)
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