How many numbers are there between 100 and 300 with 2 in the end and 2 in the beginning

10 . . . . . . .
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10
ex 202,212,222,232,242,252,262,272,282,292
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answer is 10.
because the numbers will be-
202,212,222,232,242,252,262,272,282,292
i.e 0 to 9 in the middle of 2s.
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10..keeping two corner positions fix there are 10 combinations
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ANS WILL BE 10.BECAUSE THE NUMBERS ARE 202 212 222 232 242 252 262 272 282 292
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total of 10 nos
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only one i.e 202
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10(202,212,222,232,242,252,262,272,282,292)
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10
202,212,222,232,242,252,262,272,282,292.
10 years agoHelpfull: Yes(0) No(0)
110
reason:all numbers from 101 to 199 having 2 at the end are only 9(i.e. 102,112,122,...192) and from 200 to 299 2 is at the beginning which is 100
so answer is 100+10=110
10 years agoHelpfull: Yes(0) No(2)
10
2_2 in between 0 to 9 there.
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we have to form three digit numbers which begin and end with 2
.i.e we have to fill only 100o's place with 0 to 9 digits,for this we have 10 choices and remaning places are filled in one way.
total chances =1*10*1 =10 (using permutations and combination )
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How many numbers are there between 100 and 300 with 2 in the end and 2 in the beginning?