A teacher gave a student the task of adding ‘N’ natural numbers starting from 1. After a while, the student reported his result as 700. The teacher replied that his result was wrong. The student realized that
he had added one number twice by mistake. Find the sum of the digits of the number which the student had added twice.

• sum of numbers starting from 1 to 36 is 666
  and it is given that sum of N natural nubers is 700
  Therefore the student added 34 number twice in the sum of N natural numbers.
  
  So, sum of the digit of the repeated number is 3+4=7
• 10 years agoHelpfull: Yes(1) No(2)