A 1 k.m. long wire is held by n poles. If one pole is removed, the length of the gap becomes 12/3m. What is the number of poles initially?

• Length after removing pole is 12/3 = 4
  
  Then before removing pole is 2 ('coz | 2 | 2 | is | 4 |)
  
  i.e. Gap between two poles is 2m
  
  1km = 1000m
  
  Then split 1000m by 2m => we have 500 sections or gaps
  
  Then no.of poles is 500 + 1st pole = 501 poles
  
  Therefore n = 501.
• 11 years agoHelpfull: Yes(17) No(2)
• if initially dere were x poles than d distance between each pole would be 1000/x-1 m
  now if 1 pole is being removed
  1000/x-2=4
  250=x-2
  x=252
• 11 years agoHelpfull: Yes(12) No(6)
• If presently there are n-1 poles now, and the space between two poles is equal and that is 1 2/3 m or 5/3 mtr (and not 12.3 =4 mtr), then
  
  no of spaces = 1000*3/5 =600
  no of poles now = 601.
  initial no of poles = 602
• 12 years agoHelpfull: Yes(10) No(12)
• if gaps were equal, then after removing gap=12/3mtr.
  this 12/3 mtr was divided equally befor,so gaps were of 12/(3*2)=>2mtrs.
  (n-1)2=1000
  n=501
• 12 years agoHelpfull: Yes(7) No(3)
• 251
  
  1000/(12/3)=250
  initially 1 more pole was there so
  250+1=251.
• 11 years agoHelpfull: Yes(7) No(9)
• ans is 252
  because 1000/4+1+1=252
• 8 years agoHelpfull: Yes(1) No(1)
• Sab glt h!
• 7 years agoHelpfull: Yes(1) No(0)
• 6 km dats r8 ans
• 7 years agoHelpfull: Yes(0) No(0)