Lina Chen invested $24,000, part at 8% and the rest at 7.2%. How much did she invest at each rate if her income from the 8% investment is two thirds that of the 7.2% investment?

• $9000 @8% & $15000 @7.2%
  
  If Amount invested at 8%=x,then Amount invested at 7.2%=(24000-x)
  Given x*8/100 =(2/3)[(24000-x)*7.2/100]
  38.4x=345600, x=9000
  So amount invested at 8%=9000 & at 7.2%=(24000-9000)=15000
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