I cannot understand how to do this problem:



Find two consecutive integers such that the sum of 2 times the first integer and 4 times the second integer is 46.



thank you

• let 1'st no. be 'x'.so 2'nd no.will be'x+1' as they are consequtive.
  now, 2x+4(x+1)=46.
  so x=7.
  no. are 7 and 8.
• 10 years agoHelpfull: Yes(1) No(0)
• et integers are x,x+1
  2x+4(x+1)=46
  6x=42
  x=7
  7,8 are required integers
• 10 years agoHelpfull: Yes(0) No(0)
• let integers are x,x+1
  2x+4(x+1)=46
  6x=42
  x=7
  7,8 are required integers
• 10 years agoHelpfull: Yes(0) No(0)
• let the 1st no=n and 2nd=n+1
  2n+4(n+1)=46
  6n=42
  n=7
  
  first no=7
  second no=8
  
• 10 years agoHelpfull: Yes(0) No(0)