There is 4 coins 1 paisa, 5 paise, 10 paise, 25 paise using these coins we have to make 50 paisa how many combination can we make

• there should be 49 combinations
  i think 4 coins mean you have only 1,5,10,25.
  p+5q+10r+25s=50
  we'll take cases for s=0,1 and 2
  for s=0,r=0,q can be 0 to 10=11 combinations
  for s=0,r=1,q can be 0 to 8=9 combinations
  for s=0,r=2=>q=0 to 6=7 combinations
  for s=0,r=3=>q=0-4=5 combinations
  for s=0,r=4=>q=0-2=3 com
  s=0,r=5=>q=0=1 com
  for s=1,r=0=>q=0-5=6 comb
  s=1,r=1==>q=0-3=4 comb
  s=1,r=2 ==>q=0-1=2 comb
  s=2,r=0,q=0,p=0==>1 comb
  hence total combinations are 49
  Note:there p's condition is already considered when we are taking values for q.
  => && ==> means not greater this is used as i.e...
  I hope this'll be useful...
• 10 years agoHelpfull: Yes(18) No(13)
• 2 combinations..
  25p+10p+5p+1pX10
  25p+10p+5pX2+1pX5
• 10 years agoHelpfull: Yes(10) No(8)
• I think the no. of combinations are zero because as said in ques there are only 4 coins to be used but the sum of all the coins(1+5+10+25=41). Thus all these coins together taken 1 at a time can not make 50 paisa.
• 9 years agoHelpfull: Yes(6) No(1)
• plz anyone can explain clearly
• 10 years agoHelpfull: Yes(3) No(0)
• 
  as we have 4 coins each the combinations would be :
  1. 25*2=50
  now we can proceed by dividing 25 in various combinations as follows :
  2.25+((10*2)+5)=50
  3.25+(10+(5*3))=50
  as we have to use all the coins the ans would be 3 combinations.
  
  
• 10 years agoHelpfull: Yes(3) No(5)
• by 5 =10 comb.
  by 10=5 comb.
  by 25=2 comb.
  by 1=50 comb.
  max=50
  total comb=67
  expected comb=17.
• 10 years agoHelpfull: Yes(3) No(6)
• only 2 combinations possible
  
  25+10+5+(1p*10)
  25+10+(5p*2)+(1p*5)
• 10 years agoHelpfull: Yes(2) No(7)
• using any 1 coin + using any two coins +...+using all 5 coins
  5c1+5c2+5c3+5c4+5c5=31
  so 31 combi is possible.
  i.e using all coins there is only one combination possible
  using 2 coins there are 5c2 combi possible=10 so on we will get 31
  
• 10 years agoHelpfull: Yes(2) No(1)
• 4C1+4C2+4C3+4C4=15 ways
• 10 years agoHelpfull: Yes(1) No(2)
• I want to Know how many coins be used to make 50paisa ???
• 10 years agoHelpfull: Yes(0) No(0)
• logic is ,
  we have 4 coins so possible combination= 2^4-1=15.
  
• 9 years agoHelpfull: Yes(0) No(0)
• Provide relevant ans plzzz
• 8 years agoHelpfull: Yes(0) No(0)
• I hope you mean that there are four denominations available and you can use any number of coins of a particular denomination to make the total sum as 50 paise.
  
  In that case it is easier to observe that number of 1 paisa coins must be multiple of 5. So let number of 1 paisa coins be 5a, 5paise be b, 10 paise be c and 25 paise be d.
  
  Thus we have, 5a + 5b + 10c + 25d = 50
  i.e. a + b + 2c + 5d = 10
  
  It's easier to calculate now with smaller values. Just check by putting d = 0, 1 and 2 and the total cases come out to be: (1 + 3 + 5 + 7 + 9 + 11) + (2 + 4 + 6) + (1) = 49
• 7 years agoHelpfull: Yes(0) No(0)
• please explain it clearly?
• 6 years agoHelpfull: Yes(0) No(0)