12 boys are working on a work which takes 18 days to get completed After 6 days of working 4

(b) 9
let the days =X
Work in a day=12*18=
After 6 days, 4 boys joined=(12+4)
M1*D1=M2*D2
12*18=12*6+((12+4)*X)
216=72+(16*X)
216-72=16*X
144/16=X
X=9 days
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18*12 =BOY DAYS
WORK LEFT=1-(6*12/18*12)=2/3
X*16/18*12=2/3
=>X=9
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(d) 9 days
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d) none of these
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Let the total work to do 108.so 12 boys can do 108/18=6 unit work a day.so 1 boy can do 6/12=1/2 unit work in one day.now 12 boys work for 6 days and do 36 unit work.so left 72 unit work.now there is (12+4)=16 boys..so dey can do 8 unit work in a day.so there is needed 72/8=9 days.ans.
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b) 9

M1 * D1= M2 * D2
12 * 18 = (12 * 6) + ((12+4) * x)
x = 9.
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m1*d1=m2*d2
12*18=(12*6)+(12+4)*x
=9
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answer is 8
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3 + 3 + (3 x 3)/100 = 6.09

Add two percentage and add multiplication of both divided by 100
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b.9
total work 12*18=12*6+16*x=9.
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12 boys are working on a work, which takes 18 days to get completed, After 6 days of working , 4 boys joined with them. How many days it takes to complete the remaining work?
Option
a) 10
b) 9
c) 8
d) none