.A gardener increased the length of his rectangle-shaped garden by increasing its length by 40% and decreasing its width by 20%. The area of the new garden:

O has increased by 8%

O has decreased by 20%

O has increased by 12%

O has increased by 20%

• has increased by 12%
  
  If (l*b)=x is initial area, then
  new area = 1.4*l *0.8*b= 1.12*l*b= 1.12 x
  increase in area= 0.12 x
  % increase in area = 100*0.12x/x= 12 %
• 13 years agoHelpfull: Yes(32) No(0)
• first assume, 100*100 any how its rect, so area 10,000
  now 140*80=11200
  11200/10000=1.12*100=112 here 100+12=112 so 12% inc...
• 13 years agoHelpfull: Yes(19) No(0)
• let length was=x
  width was=y.
  new area=(140x/100)*(80y/100)=112xy/100.
  area increased=((xy-112xy/100)/xy)*100=12 %
• 8 years agoHelpfull: Yes(0) No(0)