The sum of three consecutive numbers is 20 more than the first no of these What is the middle number

let no are x-1,x,x+1
a/q
3x-20=x-1
=>x=19/2
hence middle no is 19/2
10 years agoHelpfull: Yes(1) No(2)
let the 3 numbers be x-1,x,x+1
then acc. to the question,

==> x-1+x+x+1=x+20
==> 3x=x+20
==> 3x-x=20
==> 2x=20
==> x=10

therefore answer is 10.
10 years agoHelpfull: Yes(1) No(0)
let the first no. be x
A/Q
x+(x+1)+(x+2)=20+x
so, x
10 years agoHelpfull: Yes(0) No(0)
let the first no. be x
A/Q
x+(x+1)+(x+2)=20+x
so, x=17/2
therefore, middle no. is 19/2
10 years agoHelpfull: Yes(0) No(0)
x+(x+1)+(x+2)=x+20
3x+3=x+20
2x=17
x=17/2=8.5
middle term is 19/2=9.5
10 years agoHelpfull: Yes(0) No(0)
x+x+1+x+2/3=20
3x+3=60
3x=60-3
x=57/3=19
so ans is: 19 20 21
10 years agoHelpfull: Yes(0) No(0)
let consecutive no are
x,x+1,x+2
then
x+(x+1)+(x+2)=x+20
2x=17
x=8.5
so
8.5+9.5+10.5=28.5
=> 8.5+9.5+10.5=(20+8.5)
so 2nd no is 9.5
10 years agoHelpfull: Yes(0) No(0)
the middle one is 19/2
9 years agoHelpfull: Yes(0) No(0)

The sum of three consecutive numbers is 20 more than the first no of these. What is the middle number?