Elitmus
Exam
Numerical Ability
Number System
if |a-2|=6 and |b+4|=2 then b/a=?
Read Solution (Total 9)
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- |a-2|=6 => a-2=6 or -(a-2)=6 => a=8,-4
|b+4|=2 => b+4=2 or -(b+4)=2 => b=-2,-6
for b/a to be minm, b should be minm and a should maxm
a max=8 & b min=-6
min(b/a)= -6/8 = -3/4
- 10 years agoHelpfull: Yes(48) No(0)
- in the question it was asked find the min value of b/a
answer -3/4, not in the options therefore d)none of these - 10 years agoHelpfull: Yes(4) No(0)
- -(a-2)=6 -(b+4)=2
=> a= -4 =>b= -6
now b/a => -6/-4 = 3/2 - 10 years agoHelpfull: Yes(1) No(1)
- b=-2
a=8
-2/8=-1/4 - 10 years agoHelpfull: Yes(1) No(4)
- 1/2 or -1/4
- 10 years agoHelpfull: Yes(1) No(0)
- -1/4 or 3/2
- 10 years agoHelpfull: Yes(1) No(0)
- b/a is minimum when b is minimum and a is maximum
so,
(a-2)=6
=> a= 8
-(b+4)=2
=>b= -6
now b/a => -6/8 = -3/4
- 10 years agoHelpfull: Yes(0) No(0)
- ans-> -1/4 and 2/3
- 10 years agoHelpfull: Yes(0) No(0)
- |a-2|=6
a=8,-4
|b+4|=2
b=2,-6
min value of b/a =(-6/8) - 10 years agoHelpfull: Yes(0) No(0)
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