Find the remainder when 3^5^9^13....33 is divided by 5.

• 3
  
  units digit of 3^x=units of 3^(x mod 4)
  here x=5^9^13..33=> x mod 4= (1)^9^13...=1
  so units digit of 3^x = 3^1 = 3
  hence remainder when divided by 5 is 3.
• 13 years agoHelpfull: Yes(7) No(0)