The great Indian mathematician Bhaskaracharya formulated this problem in the twelfth century for his teenaged prime number aged daughter Lilavati. He also authored the eponymous Lilavati, a compendium of mathematical puzzles, in which the number of problems that use this formula is the sum of two prime numbers. The product of the two prime numbers is smaller than the total number of problems in the Lilavati. Now if the difference of any two numbers is 6 and their product is 18. what is the sum of their squares?

O 72.00

O 54.00

O 42.00

O 44.00

• 72
  
  If x,y are two numbers, then
  x-y = 6 => (x-y)^2 = x^2+y^2-2xy = 36
  Now xy = 18
  x^2+y^2-2*18 = 36
  x^2+y^2=72
• 12 years agoHelpfull: Yes(23) No(3)
• 72
  if x,y are two numbers, then
  x-y=6 =>(x-y)^2=x^2+y^2-2xy=36
  now xy =18
  x^2+y^2-2*18=36
  x^2+y^2-36=36
  x^2+y^2=36+36
  x^2+y^2=72
  
• 12 years agoHelpfull: Yes(6) No(2)
• 54
  
  If x,y are two numbers, then
  x-y = 6 => (x-y)^2 = x^2+y^2-2xy = 36
  Now xy = 18
  x^2+y^2-18 = 36
  x^2+y^2=54
  
• 12 years agoHelpfull: Yes(4) No(17)
• ans: A
  here x-y=6 and xy=18 according to given data
  formula (x-y)^2=x^2+y^2-2xy
  we need x^2+y^2=(x-y)^2+2(xy)
  substitue values x-y=6 and xy=18
  x^2+y^2=36+2(18)
  ans : 72
• 12 years agoHelpfull: Yes(4) No(0)