The distance between two stations is 100 km. 2 cars start from A and B at the same time and return to the original station with speed 48 km/hr and 100 km/hr. Find the time gap between their two meetings.

• First time they will meet after travelling 100 kms together after time 100/100+48 = 100/148 hrs.
  
  second time, they will meet when slow driver has travelled a distance of x kms and fast driver has covered distance 100+x km in same time after time x/48 hrs.
  1.e
  x/48 = (100+x)/100
  or
  100x= 4800 +48x
  52x = 4800
  x/48 = 100/52
  
  so diff in meetings = (100/52- 100/148) =1.92 - 0.68 = 1.24 hrs
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