An express train takes 3 seconds to enter tunnel which is 1 km long.
If it is traveling at 120 km an hour, how long will it take to pass completely through the tunnel

• Total time = 3+3600/120 = 3+30 = 33 secs
• 13 years agoHelpfull: Yes(2) No(0)
• speed = 120km/hr
  enter a tunnel,, means that the train covers a distance equal to its own length
  so (120*5/18)=x/3 where x= length of train
  hence x= 100 mtrs
  to pass completely train has to travel a distance =(x + tunnel length) that is 1100mtrs
  so (1100/t)=(120*5)/18
  t= 33 sec(ANSWER)
• 10 years agoHelpfull: Yes(1) No(0)
• Length of the train = (120*3/3600)*1000 m = 100m
  To completely pass through the tunnel, distance covered = 100 + 1000 + 100 = 1200m = 1.2 km
  Therefore, time = 1.2/120 hr = 1/100 hr = 3600/100 sec = 36 sec Ans.
• 10 years agoHelpfull: Yes(1) No(0)
• 33secs..
  given distance=1km
  speed=120km/hr
  so,time taken to see outside of the tunnel is 1/120/1hr=1/120 hrs=30secs
  the whole train takes 3 more secs so, 30+3=33secs..
  
• 10 years agoHelpfull: Yes(0) No(0)
• speed of train = 120 km/hr ==> (300/9)m/sec.
  length of train (300/9)*3 ==>100m
  
  time taken by train to pass completely tunnel= (length of tunnel +length of train)/speed of train
  
  (1000+100)/(300/9)= 33 sec.
• 9 years agoHelpfull: Yes(0) No(0)
• 33 secs
  length of train =100m as it takes 3 sec with 120 km/h speed to enter
  lenth of tunnel =1000m
  total distance to be travelled =1100m with speed 120km/h
  time=33 sec
• 9 years agoHelpfull: Yes(0) No(0)
• 33 sec half min plus 3sec
• 9 years agoHelpfull: Yes(0) No(0)
• 3 sec
  120kmph=120*5/18=100/3mpsec
  the length of train=3*100/3=100m
  distance=100+1000=1100m
  speed=100/2 mps
  time=distance/speed=1100*3/100=33sec
• 7 years agoHelpfull: Yes(0) No(0)
• S=d/t
  120×5/18 = l/ 3
  l= 100
  Now
  120×5/18 = 1100 / t
  t=33 secs
• 7 years agoHelpfull: Yes(0) No(0)