TCS
Company
A, B, C, D, E, F and G are seven positive integers.
I) AB is odd. II) C+ DE is odd.
III) AD is odd. IV) F – G is odd.
How many of the above integers are odd?
a) 5 b) 3 c) 4 d) 6
Read Solution (Total 4)
-
- ans:6=A,B,C,D,F,G;Emust be even
1.AB odd means (odd x odd = odd) A&B odd;
2.AD odd means (odd x odd = odd) D odd;
3.case1:C+DE odd means(odd+even = odd) so C must be odd E must be even;
4.case2:C+DE odd means(odd+even = odd) so E must be odd C must be even;
it meanes C or E odd.(with selp of step5 c must be odd)
5.FACG odd means (odd x odd = odd) F,A,C,G is odd;
- 13 years agoHelpfull: Yes(28) No(1)
- Answe is a) 5
Since AB is odd, B is odd - 1
Since C + DE is odd, either C or E is odd - 1
Since AD is odd, D is odd - 1
F & G are odd - 2 - 13 years agoHelpfull: Yes(0) No(14)
- answer is c because AB is odd so B is odd
c+DE is odd so eiher c is odd or E is odd
AD is odd so D is also odd
F-G is odd so in his case also either of F or G is odd.
there are 4 no which are odd - 9 years agoHelpfull: Yes(0) No(0)
- kiran F and G both cannot otherwise F-G will be even
so ans is 5 - 9 years agoHelpfull: Yes(0) No(0)
TCS Other Question