A monkey climbs 6 mts and fals 3mts in alternate mins.then time taken to climb a tree of 60 mts

• In 1st min , monkey climbs up 6mts
  Int 2nd min, if falls 3mts --> so 6-3= 3mts
  
  So In 2 mins, It can climb 3mts
  In 10 mins, 10/2 * 3 = 15 mts
  In 20 mins, 20/2 * 3 = 30 mts
  In 30 mins, 30/2 * 3 = 45 mts
  In 34 mins, 34/2 * 3 = 51 mts
  At 35th min, It ll climb up 6 mts ... So 51+6=57 mts
  At 36th min, it ll fall 3 mts ... So 57-3 = 54 mts
  At 37th min, It ll climb up 6mts... So 54+6 = 60 mts...
  
  The tree is of height 60 mts... So once it reach the top, it ll not fall back...
  [Note here the monkey ll climb up 6mts in every odd mins nd falls 3mts in every even mins... Bcozzz it starts by climbing up..]
  
  Ans : 37 mins
  
• 10 years agoHelpfull: Yes(24) No(1)
• Monkey climbs 3 mtrs net in 2 mins.
  monkey will climb 54 mtrs in 36 mins.
  in 37th min, it will reach top of 60 mtr tree.
  so 37 mins.
• 10 years agoHelpfull: Yes(3) No(1)
• 19 min because total distance covered by monkey in 1 min is (6-3)=3 min for 19 min it will cover 57 mts after reaching this distance at 20th min it will reach 63 min. so the ans is
• 10 years agoHelpfull: Yes(0) No(3)