SOLVE

2Y^2-3Y+5=0

• For the equation 2y^2-3y+5=0,
  we are not getting any roots, so we have an alternate solution that
  -b+/-sqrt(b^2-4ac)/2*2)
  ==> here a=2, b=-3 and c=5
  ==> -(-3)+-sqrt((-3)^2-4*2*5)/2*2
  ==> 3+-sqrt(9-40/4
  ==> 3+-sqrt(-31)/4
  ==> for negative signs in sqrt will dont have any roots
• 10 years agoHelpfull: Yes(0) No(0)