number of zeros b/w 1to 999??

• ans: 189
  
  no. of zeroes in 2 digit no.s => (_)(0) => 9 no.s => 9 zeroes
  
  in 3 digit no.s
  
  (_)(_)(0) => 9*9=81 n0.s => 81 zeroes
  (_)(0)(_) => 9*9=81 no.s => 81 zeroes
  (_)(0)(0) => 9 no.s => 9*2=18 zeroes
  
  total number of zeros b/w 1 to 999 = 9 + 81 + 81 + 18 = 189
• 10 years agoHelpfull: Yes(72) No(2)
• Ans 189
  1-100=11 0's, 101-200=20 0's similarly
  Than 101-900=160
  And 901-999=18
  Now 11+160+18=189
• 10 years agoHelpfull: Yes(10) No(0)
• ans: 189
  
  no. of zeroes in 2 digit no.s => (1)(0),(2)(0),…(9)(0) => 9 no.s => 9 zeroes
  
  in 3 digit no.s
  
  (1)(1)(0),(1)(2)(0),……(9)(9)(0) => 9*9=81 n0.s => 81 zeroes
  (1)(0)(1),(1)(0)(2),……(9)(0)(9) => 9*9=81 no.s => 81 zeroes
  (1)(0)(0),(2)(0)(0),…….(9)(0)(0) => 9 no.s => 9*2=18 zeroes
  
  total number of zeros b/w 1 to 999 = 9 + 81 + 81 + 18 = 189
• 10 years agoHelpfull: Yes(3) No(0)
• 246
  to determine the no of zeroes in a factorial no,,we divide it by 5 and the quotient gives us the no of zeroes
  here 1-999=999! so on dividing 999 by 5 we get 246,,actually we only get 995,,we take the nearest value
  
  
• 10 years agoHelpfull: Yes(1) No(9)
• ans:189
  
  no of zeros between 1 to 999
  
  at the end digit: (990-10)/10+1= " 99 "
  
  at the middle digit:
  extra 1 zeros for 100,200,300.....900 total " 9 " which are not included in 99
  and
  extra (9 zeros in 101,102.......109)+(9 zeros in 201,202...209)+.....+(9 zeros in 901,902...909)
  
  =9*9= " 81 " zeros
  
  so total= 99 +9 +81= 189
• 9 years agoHelpfull: Yes(1) No(0)
• 10,20,.....100=11 zeros
  lly,110,120......200=11 zeros
  ...
  .
  .
  .
  910,920,.....990=10
  so,11*9+10=109
• 9 years agoHelpfull: Yes(1) No(0)
• zeros in the two digit number _ _ if u fix 0 at units place then there will be total 9 numbers 9 zeros,similarly for three digit number _ _ _ fix zero at zero at units place first then remaining places can be filled in (9*9)=81 ways so *! zeros illy when zero is at tens place (9*9)=81 numbers 81 zeros ,now _ _ _ zero can be at two positions units and tens so (numbers are possible so total zeros are 9+81+81+18=189 will be the answer
• 10 years agoHelpfull: Yes(0) No(0)
• 10,20,30,40,50,60,70,80,90,100 so no. of zeroes are 11
  101....110 is 10 then 120,130,140,150,160,170,180,190,200 is 10
  similarly for 201 to 300 is 20 etc till 801 to 900
  901..910 is 10 then 920,930,940,950,960,970,980,990
  no. of zeroes =11+8*20+19=11+160+18=189
• 10 years agoHelpfull: Yes(0) No(0)
• 9*1+9*9*1+9*1*9+9*2!=9+81+81+18=189
• 10 years agoHelpfull: Yes(0) No(0)
• ans:99
  n0. of 0's b/w 0 to 99 is 10
  so total no. of 0's b/w 0 to 999 is 100
  and question asks 1 to 999 so 100-1= 99
• 9 years agoHelpfull: Yes(0) No(3)
• from 1-100 (10,20,30,40,50,60,70,80,90,100) no. of zeroes are 11
  from 101-200 (101-110 0's --->10 + 120..200 0's ----> 10) no. of zeroes are 20
  from 101-200 (201-210 0's --->10 + 220..300 0's ----> 10) no. of zeroes are 20
  from 101-200 (301-310 0's --->10 + 320..400 0's ----> 10) no. of zeroes are 20
  from 101-200 (401-410 0's --->10 + 420..500 0's ----> 10) no. of zeroes are 20
  from 101-200 (501-510 0's --->10 + 520..600 0's ----> 10) no. of zeroes are 20
  from 101-200 (601-610 0's --->10 + 620..700 0's ----> 10) no. of zeroes are 20
  from 101-200 (701-710 0's --->10 + 720..800 0's ----> 10) no. of zeroes are 20
  from 101-200 (801-810 0's --->10 + 820..900 0's ----> 10) no. of zeroes are 20
  from 101-200 (901-910 0's --->10 + 920..990 0's ----> 08) no. of zeroes are 18
  so total zeroes are 11+(8*20)+18 = 189
• 7 years agoHelpfull: Yes(0) No(0)
• 1 to 100=11
  101 to 200=20
  201 to 300=20
  301 to 400=20
  401 to 500=20
  501 to 600=20
  601 to 700=20
  701 to 800=20
  801 to 900=20
  901 to 999=18
  total zeros=11+(20*8)+18=189
• 7 years agoHelpfull: Yes(0) No(0)