Elitmus
Maths Puzzle
Numerical Ability
Probability
A container contain Red,white,Blue,Green balls(without replacement)
there is condition:
a) Drawn four red balls
b)Drawn one white and three red balls
c)Drawn one white,two blue and two red balls and
d)Drawn one white, one blue and one red
find minimum number of balls to satisfy that condition
option are
1)10
2)19
3)21
4)i forget please provide solution...
Read Solution (Total 8)
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- ans is 17 as red balls-10,blue-3,white-3,green-1 we have to take green as min 1 because container contains green baals so toal answer is 17
- 10 years agoHelpfull: Yes(18) No(1)
- I think the answer is 7
Because
The total number of balls required to satisfy all the above conditions is
4 red balls, 1 white ball and 2 blue balls. - 10 years agoHelpfull: Yes(11) No(10)
- here , without replacement ...so i think ... 4 + 1 + 3 .... 17 balls dudes
- 10 years agoHelpfull: Yes(4) No(1)
- 4-red,1-white,2-blue and one green
- 10 years agoHelpfull: Yes(2) No(5)
- Answer is 16.
- 10 years agoHelpfull: Yes(1) No(5)
- if the 4th option is 8 then ans is 8 otherwise ans is 10
reason-the maximum number of red,white and blue ball picked up are 4,1,2 respectively so these 7 balls must be contained after that there is green ball also,so the lowest number is 8 and second lowest is 10. - 10 years agoHelpfull: Yes(0) No(1)
- i think it is 17 as it says without replacement
- 10 years agoHelpfull: Yes(0) No(2)
- How 17??please explain
- 10 years agoHelpfull: Yes(0) No(1)
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