Elitmus
Exam
Logical Reasoning
Cryptography
AGE
*OAT
------
SOAR
HOG
GOTO
------
GECOIR
Read Solution (Total 18)
-
- A = 3
G = 1
E = 7
O = 5
T = 8
S = 2
R = 6
H = 9
C = 0
I = 4
AGE(317) * OAT(538) - 10 years agoHelpfull: Yes(9) No(1)
- if u guys see this problem then u'll find that "G=1" i.e at the last row
"G O T O" where "G=G" it means 'G=1', put the value "G=1" in place of 'G' then there u'll get
"A G T * A= H O G" and u know 'G' value then find what r the possible multiplication r there which give "1" u'll find (3*7 or 7*3) from this u'll get the value of "A & T" if u put "A=7 & E=3" the u'll get "O=9" and it is not possible bcoz if "O=9" then the value of 'G' will change, so cross check again "A=3 & E=7" it will satisfy the condition and u'll get "O=5 & H=9"
Now u've "A=3,G=1,E=7,O=5,I=4,& H=9"
now check "A G E * O" i.e "3 1 7 * 5" after multiplication u'll get "T=8"
Now u've "A G E * O A T" (3 1 7 * 5 3 8) u'll get "S=2 & R=6" - 10 years agoHelpfull: Yes(3) No(1)
- 317
*538
------
2536
951
1585
----------
170546
- 10 years agoHelpfull: Yes(2) No(0)
- 1) Here O*E=O. This is only possible with values (5,3) (5,5) (5,7) (5,9) & (2,6) (4,6) (6,6) (8,6).
But as either E= O+1 or E= O+2. So we left with only 2 pairs (5,7) &(4,6)
2) Now lets assume O=5 & E=7.
3) We can also conclude that value of A should be small. Firstly we try with A=2, here condition fails. So we take A=3.
Assuming these we can proceed for solutions.
Solution is 317 * 538. - 10 years agoHelpfull: Yes(2) No(0)
- 317
*538
----
1) O*E
O=5 or 2,4,8
and
E=3,7,9 or 5
2) as 3O=O
therefore O=5
and E=7 (as E!=6)
3) then solve similarly you will reach the answer. - 10 years agoHelpfull: Yes(1) No(2)
- It's E=3,7,9 or 6
- 10 years agoHelpfull: Yes(0) No(0)
- how to assign a value 3 to A ?
any 1 explain me please......
A = 3
G = 1
E = 7
O = 5
T = 8
S = 2
R = 6
H = 9
C = 0
I = 4 - 10 years agoHelpfull: Yes(0) No(0)
- can anyone explain it clearly
- 10 years agoHelpfull: Yes(0) No(0)
- Please Explain it.
- 10 years agoHelpfull: Yes(0) No(0)
- Please can explain properly how you are assigning the values for alphabets..
- 10 years agoHelpfull: Yes(0) No(0)
- 3 1 7
* 5 3 8
-------
2 5 3 6
9 5 1
1 5 8 5
-------------
1 7 0 5 4 6 - 10 years agoHelpfull: Yes(0) No(2)
- 317
538
-------
2536
951
1585
------
170546
-------
- 10 years agoHelpfull: Yes(0) No(0)
- in addition 3 O is their so O must be 5.then start with 2nd step..H is a multiple of A*A so A will be 1,2,3.1 is not possible so check for 2 and 3.after processing you will get the answer.
- 10 years agoHelpfull: Yes(0) No(0)
- 317
*538
----
2536
951
1585
-------
170546 - 10 years agoHelpfull: Yes(0) No(0)
- Its 317 * 538
as O * E = O so possible combination will be 5*7 , 5*3, 5*9 and 2*6, 4*6, 8*6
- 10 years agoHelpfull: Yes(0) No(0)
- 317
538
------
2536
951
1585
-----
170546 - 10 years agoHelpfull: Yes(0) No(0)
- Sum of three O equals to O it can only happen with 5. So O will be equal to 5.
Now for 'A' multiplication with AGE we are getting A*E=G and A*G=O and A*A=H.
So if we will consider last one i.e A*A=H and there is no carry so it can be either 2*2=4 or 3*3=9.
Now if value of A will be consider as 3 then we will have to put value of E such that after 3*E=? and 3*?=O(5).
So in this case if we will put ?=7 then we will get A(3)*E(7)=21(G) and A(3)*G(1)=3+2(carry) i.e =5(O) a satisfied value.
Now we need to put value of T such that after multiplying it with E(7) when it again multiply with G(1) it should be equal to A(3).
So it can be only possible when we will multiply E(7) with T(8)=56 and carry(5) and then T(8)*G(1)=8+5=13(A)....
Now it becomes easier to find remaining values.
- 10 years agoHelpfull: Yes(0) No(0)
- first we can see that O+O+O=O so only no which can possile is 5
now AGE
*O
----
-5-5
so we will asume E as 7
when we put 7 it will be
1585 now we check that no to other and the value will be satisfied
now AGE
*A
---
HOG
951
NOW WE get all the answer
A =3,G =1,E =7,O =5,T =8,R =6,H =9, - 10 years agoHelpfull: Yes(0) No(0)
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