When I was married 10 years ago, my wife was the sixth member in the family. Today, my father died,
and a baby was born to me. The average age in my family today is what it was when I was married.
How old was my father when he died?
1. 50 years
2. 60 years
3. 70 years
4. Indeterminate

• Let when I was married the avg age of my family was x years and total age=6x
  Now total age is 6x +60. So my father's age was 60...
• 12 years agoHelpfull: Yes(9) No(16)
• If x was average age 10 years ago, then total age 10 years ago = 10x.
  Total age of 6 persons before death of father = 10x+60
  Total age of 6 persons ( excluding father and adding son of zero age) after death of father = 60x as average of family is x again.
  
  Hence age of father at time of death = x+60-x = 60 years
• 12 years agoHelpfull: Yes(5) No(14)
• let the fathers age 10 years back be x years
  so present age when he died is x+10 years .
  now assume the age of the rest of the members to be y years.
  so the average age of the 6 members 10 years ago would be (x+y)/6...eqn1
  now ,at the present time the father has died so x becomes 0 and the tatal age of the rest of the family members ha increased by (5*10)years..it shuld be noted that the age of the new baby is 0.so the eqn 2 becomes (y+50)/6 =the average age.
  on solving we get x=50 .
  so the present age =x+10=50+10=60
• 10 years agoHelpfull: Yes(3) No(0)
• dipin - y did u included 60x after d death of d father...avg is same hence u included x i understood bt y 60??can u plz explain?????
• 11 years agoHelpfull: Yes(2) No(0)