Book Maths Puzzle Percentage

Okay, Mary has two investments whick yeild anually an income of $996.l One investment yeilds 7%; the other 8%. How much is invested in each if the total amount invested is $12,800?

Read Solution (Total 1)

$2800 @7% ,$10000 @8%

If the amount invested at 7%=x, then at 8%= (12800-x)
Given, (x*7/100)+[(12800-x)*8/100]=996
On solving,x=2800
other investment=12800-2800=10000
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