A person starts with the speed of u/1 kmph and returns with the speed of u/2 kmph, what is his average speed.

• average speed =2xy/x+y
  
  x=u/1 y=u/2
  2*u/1*u/2/u/1+u/2=2u/3
• 13 years agoHelpfull: Yes(36) No(0)
• average speed===2/3u
• 13 years agoHelpfull: Yes(12) No(11)
• average speed =
  (2*u/1*u/2)/(u/1+u/2)=2u/3
• 13 years agoHelpfull: Yes(6) No(1)
• average speed =2xy/x+y
  
  x=u/1 y=u/2
  [2*(u/1)*(u/2)]/[(u/1)+(u/2)]=2u/3
• 13 years agoHelpfull: Yes(6) No(1)
• formula is : 2xAxB/(A+B)
  
  A=1
  B=2
  
  So, 2x1x2/(2+1)=4/3u
  
  Answer is 4/3u
• 13 years agoHelpfull: Yes(2) No(14)
• 3u/4.
  (sum of two speed)/2
• 13 years agoHelpfull: Yes(2) No(19)