A does 3/4 of piece of work in 24 days he then calls in B and both together complete the remaining work in 4 days.how long would B alone take to do entire work?

• 32 days
  
  3/4 work is done by A in 24 days
  
  Number of days required by A to do the entire work = 24*4/3 = 32days
  Number of days required by A to do 1/4 work = 32*1/4 = 8 days
  
  Let B take x days to finish 1/4 work alone
  A and B together take 4 days
  
  8*x/(8+x) = 4
  8x = 4x + 32
  x = 8
  
  To finish the entire work B takes = 8*4 = 32days
  
• 10 years agoHelpfull: Yes(1) No(0)
• A done 3/4th work in 24 days means A can do complete work in 24*4/3 = 32days.that means remaining 1/4th work in 8 days.
  let B take X days to finish 1/4th part alone then
  (1/8)+(1/x)=(1/4)
  x=8
  the B can finish total work in 8*4=32 days
• 10 years agoHelpfull: Yes(1) No(0)