A person travels through 5 cities - A, B, C, D, E. Cities E is 2 km west of D. D is 3 km north-east of A. C is 5 km north of B and 4 km west of A. If this person visits these citiesin the sequence B - C - A - E - D, what is the effective distance between cities B and D?

• make diagram first, then traverse according to B C A E D
  u can find 5+4=9 (B to A)
  A to E is not given but u can see it as 1.5 or 2 km so B to E is 10 km
  now E to D is 2 km
  total=5+4+1.5+2=12.5
  or 5+4+2+2=13 whichever is given in option will be the answer.
  in original question from accenture 13 is given and is right answer.
• 11 years agoHelpfull: Yes(27) No(10)
• Making a diagram , we get
  Horizontal distance of B and D( Eto w) = 6.12 km
  Vertical distance of B and D( Nto S) = 7.12 km
  
  Direct distance = 9.3 kms
• 12 years agoHelpfull: Yes(4) No(28)
• sankho upadhyay BC+AC+ED = 11
  Think of AED as triangle, so AE should be greater than 1 and less then 5 as in a triangle 3rd side < sum of two sides and > difference of two sides
  Only 13 satisfies this condition.
• 7 years agoHelpfull: Yes(1) No(0)
• Ans will be (5+4+3+2)=14 km
• 11 years agoHelpfull: Yes(0) No(23)
• 5+5+2+sqrt(5)=14.23
• 10 years agoHelpfull: Yes(0) No(5)