A does 3/4 of a piece of work in 24 days .He can calls in B and both of them together complete the remaining work in 4 days . How long would B alone take to do the entire work ?

• A does 3/4 work
  3/4 work in--> 24 days
  1 work in --> x days
  x = 4/3 * 24 => x=32 days
  A ll complete the whole work in 32 days
  Then A's 1 day work = 1/32
  
  Remaining work left = 1-3/4 => 1/4
  A+B finish 1/4 work in --> 4 days
  A+B finish 1 work in --> x days
  x = 4*4 = 16 days
  A+B ll finish the whole work in 16 days
  Then A+B's 1 day work = 1/16
  
  Therefore B's 1 day work = (A+B)'s 1 day work - A's 1 day work
  => 1/16 - 1/32 => 16/512 = 1/32
  So B ll finish the work alone in 32 days
  
  Ans : 32 days
  
• 10 years agoHelpfull: Yes(10) No(0)
• 32 days
  A takes 32 days for entire work
  a&b do 1/4 work in 4 days so they complete work in 16 days
  so
  1/32+1/B=1/16
  so B=32 days
• 10 years agoHelpfull: Yes(0) No(0)