IBM
Company
Logical Reasoning
Number Series
(1)-3,6,1,-2,4,-1,21,2,-3,?
(2)22,19.5,21.45,33,26,15,-1,?
(3)49,39,37,33,26,15,?
(4)35,57,12,14,2,7,9,42,67,?
(5)8,6,22,26,54,58,86,90,118,?
(6)11,8,17,14,23,24,31,32,?
(7)8,16,3,27,4,8,7,19,2,0,7,?
(8)5/6,1/3,1/2,1/2,2/8,1/4,5/6,1/6,2/3,1/2,1/3,?
(9)100,98,95,90,83,?
(10)0,8,12,26,23,?
(11)18,24,5,21,8,27,17,23,4,24,30,?
(12)2,3,10,15,26,3550,?
(13)7776,625,64,9,?
(14)
Read Solution (Total 10)
-
- (1) (-3,6,1),(-2,4,-1),(-1,2,-3),(x , y, z)
In each group, 1st number increases by "1" => {-3,-2,-1,x} => x=0
In each group, 2nd number decreases by "2" => {6,4,2,y} => y=0
In each group, 3rd number decreases by "2" => {1,-1,-3,z} => z=-5
Ans : (0,0,-5)
(3)49,39,37,33,26,15,?
I think series might be wrong...
40,39,37,33,26,15,x
40 - 39 = 1
39 - 37 = 2 [prev diff + 1]
37 - 33 = 4 [prev diff + 2]
33 - 26 = 7 [prev diff + 3]
26 - 15 = 11 [prev diff + 4]
15 - x = 16 [prev diff + 5]
x = -1
Ans : -1
(4)(35,5,7,12),(14,2,7,9),(42,6,7,x)
35/5 = 7
5 + 7 = 12
14/2 = 7
2 + 7 = 9
42/6 = 7
6 + 7 = 13
Ans : 13
(5)8,6,22,26,54,58,86,90,118, x
Divide the series into 2
(8, 22, 54, 86, 118) ( 6, 26, 58, 90, x)
(8*3) - 2 = 22
(8*7) - 2 = 54
(8*11) - 2 = 86
(8*15) - 2 = 118
(6*4) + 2 = 26
(6*9) + 4 = 58
(6*14) + 6 = 90
(6*19) + 8 = 122
Ans : 122
(6)11,8,17,14,23,24,31,32,x
Alternate prime no's - 5
11
13 - 5 = 8
17
19 - 5 = 14
23
29 - 5 = 24
31
37 - 5 = 2
41
Ans : 41
(7) (8,16,3,27),(4,8,7,19),(2,0,7,x)
8 + 16 + 3 = 27
4 + 8 + 7 = 19
2 + 0 + 7 = 9
Ans : 9
(8)(5/6,1/3,1/2), (1/2,2/8,1/4),(5/6,1/6,2/3),(1/2,1/3, x)
5/6 - 1/3 = 1/2
1/2 - 2/8 = 1/4
5/6 - 1/6 = 2/3
1/2 - 1/3 = 1/6
Ans : 1/6
(9)100,98,95,90,83,x
Difference of prime numbers
100 - 98 = 2
98 - 95 = 3
95 - 90 = 5
90 - 83 = 7
83 - x = 11
x = 72
Ans : 72
(11)(18,24,5),(21,27,8),(17,23,4),(24,30,x)
18 + 6 = 24
24 - 19 = 5
Similarly 24 + 6 = 30
30 - 19 = 11
Ans : 11
(12)2,3,10,15,26,35,50, x
1^2 + 1 = 2
2^2 - 1 = 3
3^2 + 1 = 10
4^2 - 1 = 15
5^2 + 1 = 25
6^2 - 1 = 35
7^2 + 1 = 50
8^2 - 1 = 63
Ans : 63
(13)7776,625,64,9,x
7796 --> 6^5
625 --> 5^4
64 --> 4^3
9 --> 3^2
2 --> 2^1
x --> 1^0 ==> 1
Ans : 1
- 10 years agoHelpfull: Yes(40) No(5)
- (10) (0,8),(12,26),(23,x)
8 - 0 = 8
26 - 12 = 14 [prev diff + 6]
x - 23 = 20 [prev diff + 6]
x = 43
Ans : 43
- 10 years agoHelpfull: Yes(13) No(2)
- (49,37,26),(39,23,15)
diff in 1st group is decreasing 12,11 next 10 so answer is 16 not -1. - 10 years agoHelpfull: Yes(3) No(4)
- 13) 7776=6^5
625=5^4
64=4^3
9=3^2
2^1=2 ans
- 10 years agoHelpfull: Yes(3) No(1)
- (13) 7776,625,64,9,?
Ans: 6^5=7776
5^4=625
4^3=64
3^2=9
2^1=2
so ans is 2 - 10 years agoHelpfull: Yes(2) No(0)
- 3)49,39,37,33,26,15
alternate term
49-12=37
37-11=26
26-10=16
ans=16 - 10 years agoHelpfull: Yes(1) No(2)
- (12) 2,3,10,15,26,35,50,?
(3-2)=1 (15-10)=5 (35-29)=9 (x-50)=13 so, x=63 - 9 years agoHelpfull: Yes(1) No(0)
- (10) 0+12+23=35
8+26+x=35
x=1 - 10 years agoHelpfull: Yes(0) No(3)
- 2.)37.5
do 33-19.5=13.5
33-15=18
now 15+22.5=37.5 - 7 years agoHelpfull: Yes(0) No(0)
- Q2: 22 (19.5, 21.45 ) 33 ( 26, 15, -1) ?
answer = 44 - 6 years agoHelpfull: Yes(0) No(0)
IBM Other Question
What is the next number of the following sequence.
1. 49, 7, 98, 16, 4, 48, 9, 3, ?
2. 36, 25, 5, ?
is there any chance to 2012 passout students in ibm,if any chance please tell me.