If a: b :: 3 : 7, then what is (5a+6b): (a-2b)?
Option
(a) 57:11
(b) -57:11
(c) 11 : 10
(d) -11 : 10

• (b)-57:11
  a/b= 3/7
  Dividing numerator & denominator of ' (5a+6b)/(a-2b) 'by b,
  [5(a/b)+6]/[(a/b)-2]= [5*(3/7)+6]/[(3/7)-2]= -57/11
• 10 years agoHelpfull: Yes(21) No(1)
• a:b=3:7
  then a =3k and b=7k k is arbitary constant
  then (5a+6b):(a-2b)=(15+42)k:(3-14)k
  =>-57:11
• 10 years agoHelpfull: Yes(8) No(0)
• 7a=3b
  (5a+6b):(a-2b)
  (5a+14a):(a-14a/3)
  19a:(-11a/3)
  -57:11
• 10 years agoHelpfull: Yes(6) No(0)
• a=3,b=7 substitute in the equation then we get the (15+42):(3-14) =-57:11
• 10 years agoHelpfull: Yes(3) No(1)
• a=3b/7
  b= 7a/3
  
  substituting,
  5(3b/7)+6b = 57b/7
  3b/7 - 2b = -11b/7
  
  puting the values in ratio :-
  ans -> -57/11
• 10 years agoHelpfull: Yes(1) No(0)
• a//b=3/7
  (5a/b +6)/(a/b)-2
  -57/11
  
  
  ans is b
• 10 years agoHelpfull: Yes(1) No(0)