A,B and C can independently do a work in 15 days. they work together for some time after which C leaves. a total of Rs 18000 is paid for the work and B gets RS 6000 more than C. for how many days did A work?

• A,B and C can independently do a work in 15 days.
  A,B and C together can do a work in 15/3=5 days.
  
  
  If A & B worked for all time, then
  C got Rs 2000, A&B got Rs 8000 each.
  cost of each man day = 18000/15= Rs 1200.
  so A& B worked for 8000/1200= 20/3 days
• 10 years agoHelpfull: Yes(2) No(2)
• 20/3 days
  
  If A,B & C together works for 'n' days
  'n' days work of A,B & C= n*[(1/15)+(1/15)+(1/15)]=n/5
  Work remained= 1-(n/5)=(5-n)/5
  Remaining work is done by A & B only for [(5-n)/5]/[(1/15)+(1/15)]=(15-3n)/2 days
  
  Given 'B' gets Rs. 6000 more than C, As A & B works for same days
  Amount of A=B, So A+B+(B-6000)=18000, So A=B=8000 & C=2000
  
  As 'A' worked for total n+(15-3n)/2=(15-n)/2 days &
  'C' worked for 'n' days, so ratio of their work & earnings
  =[(15-n)/2]/n = 8000/2000, n=15/9
  So 'A' worked for (15-n)/2=[15-(15/9)]/2= 20/3 days
• 10 years agoHelpfull: Yes(2) No(2)
• Total work = 60
  A — 4 ,, B– 3 ,,,, C — 2
  let A &B work for x days
  Then work done by A = 4x
  B = 3x
  C =60- (4x+3x)
  So ratio of their share
  4x : 3x : 60-7x
  Difference between b and c = 3x – (60-7x) = 10x – 60
  ( 10x – 60)/60 * 18000 = 6000
  so,x =8
• 5 years agoHelpfull: Yes(0) No(0)