A vessel has a milk solution in which milk and water are in the ratio 4:1. by addition of water to it, milk solution with milk and water in the ratio 4:3 was formed. on replacing 14 L of this solution with pure milk the ratio of milk and water changed to 5:3. what is the volume of the water added?

• 32L
  M:L= 4:1 => 4x of milk and 1x of water
  after adding water M:W =4:3 =>4x of milk and 3x of water(means 2x extra water is added)
  now , 14 L IS REPLACED WITH PURE MILK
  that means (4x/7x)*14 = 8L of pure milk is removed and (3x/7x)*14 = 6L of water is rmoved from (4x +3x)L of solution
  now adding 14L pure milk
  (4x-8+14)/(3x-6)=5/3
  on solving x =16
  therfore 2x = 32 L OF WATER is added
• 10 years agoHelpfull: Yes(6) No(2)
• 32 litres of water was added.
  
  M....W
  64..16.. initially .... ratio = 4:1
  64..48... After adding 32 litre water... ratio = 4:3
  56..42... removing 14 litre mixture
  70..42.... adding 14 litre pure milk .... ratio = 5:3
• 10 years agoHelpfull: Yes(2) No(3)
• after addition of water the ratio is 4:3. so in 14 litres of sol. there is 8 l of milk and 6 lt of water. so when 14 lits of milk is added, actually only 6 lts of milk is added and the water composition is reduced by 6 l.
  4x+6/3x-6 = 5/3
  x comes to 12 . so water added is 24.
• 10 years agoHelpfull: Yes(1) No(3)
• Ans :36 ltr
  Let 5x be solution, milk(4x) water(x)
  Now y ltr wtr b added then 4x/(x+y)=4/3 on silving we get y=2x
  Total solution nw is 5x+2x=7x fom dis 14 ltr taken out which means 8 ltr of milk and 6 ltr of wtr
  Hence m:w=(4x-8):(3x-6) nw 14 ltr milk added
  New ratio m:w=(4x-8+14):(3x-6)=5:3
  On solving x=18
  Watr added =2x=36
• 10 years agoHelpfull: Yes(1) No(4)