The ratio between the boys and girls in a class in 6:5 if 8 more boys join the class and two girls leave the class then the ratio becomes 11: 7 What is the number of boys in the class now?
Option
(a) 28
(b) 38
(c) 44
(d) 36
(e) None of these

• 44
  
  Let the number of boys and girls at first be x and y
  x/y = 6/5
  5x = 6y
  x = 6y/5
  
  (x+8)/(y-2) = 11/7
  7x + 56 = 11y - 22
  42y/5 + 56 = 11y - 22
  13/5*y = 78
  y = 30
  
  x = 36
  
  Number of boys in the class at present = 36+8 = 44
  
• 10 years agoHelpfull: Yes(17) No(0)
• (6x+8)/(5x-2)=11/7
  42x+56=55x-22
  x=6
  
  so
  6(6)+8=44
• 9 years agoHelpfull: Yes(10) No(0)
• suppose boys 6x
  girls 5x
  (6x+8/5x-2)=11/7
  x=6
  no. of boys= 6x+8=44
  ans is c
• 9 years agoHelpfull: Yes(2) No(0)
• 6x+8/5x-2=11/7
  x=6
  boys=6x=6*6=36
  ans.d
• 8 years agoHelpfull: Yes(1) No(5)
• ans : 44
  6x+8/5x-2=11/7
  x=6
  6x+8=44
• 8 years agoHelpfull: Yes(1) No(0)
• (c) 44
  let, the number of boys= x
  girls=y
  according to the given infromation, the ratio be-
  x/y=6/5 ---------(1)
  After joining of 8 boys and leave of 2 girls-
  (x+8)/(y-2)=11/7 ............ (2)
  By solving the equation (1) and (2), u'll get....
  x=36 and for finding the final number of boys add 8,
  So, the answer wil be 36+8=44.
• 8 years agoHelpfull: Yes(1) No(0)
• 11:7
  11/18x6
  3x11
  33
• 7 years agoHelpfull: Yes(1) No(0)
• MAY BE THE TIME TAKING PROCESS BUT ANS IS SURE CORRECT
  B/G=6/5; (B+8)/(G-2)=11/7;
  =>G=(5B/6); {(B+8)/[(5G/6)-2]}=11/7;
  =>(6B+48)/(5B-12)=11/7;
  =>42B+336=55B-132;
  =>13B=468
  =>B=36(ANS)
• 8 years agoHelpfull: Yes(0) No(1)
• 6x+8/5x-2=11/7
  
  42x+56=55x-22
  
  14x=78
  
  x=78/14
  
  x=6
  
  6x= 6*6=36
  
  6x+8=36+8=44
  
  total boys= 44
  
• 8 years agoHelpfull: Yes(0) No(0)
• let 'x' be common factor,
  BEFORE CHANGE:
  No.of girls in the class =5x,
  No.of boys in the class=6x,
  AFTER CHANGE:
  No.of girlsin the class=5x-2,
  No.ofboys in the class=6x+8,
  NEW RATIO:
  (6x+8)/(5x-2)=11/7,
  then x=6,
  total no.of boys (AFTER CHANGE) =44,
  total no.of boys(BEFORE CHANGE)=36,
  ANS:44
  
• 8 years agoHelpfull: Yes(0) No(0)
• let 'x' be common factor,
  BEFORE CHANGE:
  No.of girls in the class =5x,
  No.of boys in the class=6x,
  AFTER CHANGE:
  No.of girlsin the class=5x-2,
  No.ofboys in the class=6x+8,
  NEW RATIO:
  (6x+8)/(5x-2)=11/7,
  then x=6,
  total no.of boys (AFTER CHANGE) =44,
  total no.of boys(BEFORE CHANGE)=36,
  ANS:44
  
• 8 years agoHelpfull: Yes(0) No(0)
• let 'x' be common factor,
  BEFORE CHANGE:
  No.of girls in the class =5x,
  No.of boys in the class=6x,
  AFTER CHANGE:
  No.of girlsin the class=5x-2,
  No.ofboys in the class=6x+8,
  NEW RATIO:
  (6x+8)/(5x-2)=11/7,
  then x=6,
  total no.of boys (AFTER CHANGE) =44,
  total no.of boys(BEFORE CHANGE)=36,
  ANS:44
  
• 8 years agoHelpfull: Yes(0) No(0)
• let 'x' be common factor,
  BEFORE CHANGE:
  No.of girls in the class =5x,
  No.of boys in the class=6x,
  AFTER CHANGE:
  No.of girlsin the class=5x-2,
  No.ofboys in the class=6x+8,
  NEW RATIO:
  (6x+8)/(5x-2)=11/7,
  then x=6,
  total no.of boys (AFTER CHANGE) =44,
  total no.of boys(BEFORE CHANGE)=36,
  ANS:44
  
• 8 years agoHelpfull: Yes(0) No(0)
• 38 because 8 are increased
• 6 years agoHelpfull: Yes(0) No(0)