A team of 8 students goes on an excursion in two cars of which one can seat 5 and the

There are 8 students and the maximum capacity of the cars together is 9.

We may divide the 8 students as follows

Case I: 5 students in the first car and 3 in the second

Or Case II: 4 students in the first car and 4 in the second

Hence, in Case I: 8 students are divided into groups of 5 and 3 in 8C3 ways.

Similarly, in Case II: 8 students are divided into two groups of 4 and 4 in 8C4 ways.

Therefore, the total number of ways in which 8 students can travel is 8C3 + 8C4 = 56 + 70 = 126.
12 years agoHelpfull: Yes(18) No(4)
total no of ways=8c5*8c3+8c4*8c4
12 years agoHelpfull: Yes(6) No(14)
Ans= 126 ways
9 years agoHelpfull: Yes(1) No(2)
hello mr.sumit gupta,

i am at big confusion after looking this problem.could you please explain me clearly
10 years agoHelpfull: Yes(0) No(0)
hi friends can any one please explain me the solution.
thanks in advance.
9 years agoHelpfull: Yes(0) No(0)

A team of 8 students goes on an excursion, in two cars, of which one can seat 5 and the other only 4. In how many ways can they travel?