There is a 4 digit no. in which 3rd digit is twice of first one. Second digit is the sum of first and third. Fourth digit is twice of third. What is the no?

• Let the 4-digit no. be "abcd"
  c = 2*a
  b=a+c
  d = 2*c => d=4a
  abcd => (a)(a+c)(2a)(4a)
  Possible values of a ll be 1 nd 2... Bcozzz a>2 implies d>10....Digits should ranges between 0 nd 9...
  If a=1, then c=2,d=4, b=3... The no. is 1324
  If a=2, then c=4,d=8, b=6... The no. is 2648
  
  Ans : 1324 (or) 2648
  
• 10 years agoHelpfull: Yes(56) No(1)
• Assume Num is : WXYZ?
  W=1st digit
  from the give question;
  Y=2W
  X=3W
  Z=4W
  Lets assume as W value,,,i.e,
  W=1; W(3W)(2W)(4W)--->1324
  W=2; 2(3*2)(2*2)(2*4)----->2648 are only value's
• 10 years agoHelpfull: Yes(4) No(1)
• x,3x,2x,4x
  1324
  
• 10 years agoHelpfull: Yes(2) No(2)
• ya the answer is 1234 or 2468
• 9 years agoHelpfull: Yes(0) No(1)