Martha is 4 times the age of her daughter,Lyndra 4 years ago she was 8 times her daughters age,after how may years will martha be twice lyndra's age
Option
a) 14y
b) 28y
c) 7y
d) 21y

• Let m nd l be the present ages of Martha nd Lyndra
  Then m=4l
  
  4 years ago
  (m-4)=8(l-4)
  m = 8l-28
  
  Equate "m"
  4l = 8l - 28
  4l = 28
  l = 7
  m = 28
  
  After x years , Martha ll be twice of Lyndra
  (m+x) = 2(l+x)
  28+x = 2*7+2x
  28+x = 14+2x
  x = 14
  So after 14 years martha and lyndra ages ll be 42 nd 21
  
  Ans : a) 14 years
• 10 years agoHelpfull: Yes(43) No(9)
• 1) Let present age ,
  linda=x and Martha= 4x
  
  2) 4 yrs ago equation like these,
  8(x-4)=(4x-4)
  after solving x=7
  
  3) present ratio of linda and martha is
  7 : 28
  now with the help of option we jst try hit nd trial method
  and answer comes ,
  
  =7+14 : 28+14
  = 21: 42
  =1:2
  so option (a) 14 is right answer...
  
  
• 9 years agoHelpfull: Yes(5) No(1)
• 14y
  
  m=4l
  (m-4)=8(l-4)
  l=7
  m=28
  
  (m+x)=2(l+x)
  x=14
  ans
• 10 years agoHelpfull: Yes(3) No(1)
• present age of Lyndra is 7 years
  after 14 years martha's age will be twice of lyndra
• 9 years agoHelpfull: Yes(2) No(1)