Today, the age of a father is thrice the age of his son. Ater 5 years the age of father will
be 2,5 times the age of his son. Theageofson today is: — - - -
(a) 20 years (b) 15 years(c) 1 8 years (d) 22 years

• (b) 15 years
  let, age of son = S years, age of father = F years
  
  F = 3*S => F = 3S
  
  after 5 years,
  (F+5) = 2.5*(S+5)
  => 3S + 5 = 2.5S +12.5 [put F=3S]
  => .5S = 7.5
  => S = 15
  age of son = S = 15 years
• 10 years agoHelpfull: Yes(27) No(2)
• let age of son be x
  let age of father 3x
  
  after 5 years
  
  age of son x+5
  age of father 3x+5
  
  so 2.5(x+5)=3x+5
  2.5x+12.5=3x+5
  so x = 15
  x=age of son = 15
  
  x+5 =
• 10 years agoHelpfull: Yes(6) No(1)
• F=3x,S=x
  where x is present age,
  after 5 year,
  F=3x+5,S=x+5
  (3x+5)=2.5(x+5),
  after simplifying,
  we get 15year
• 9 years agoHelpfull: Yes(2) No(0)
• 3x+5=5/2(x+5)
  x=15 years
• 9 years agoHelpfull: Yes(1) No(0)
• F=3*s => F=3S ----(1)
  F+5=2.5(S+5) -----(2)
  On Solving 1 & 2 We get...
  3S+5=2.5(S+5) => 3S+5=2.5S+12.5
  3S-2.5S=12.5-5
  0.5S=7.5 => S= 7.5/0.5 ===>S=15
  
• 9 years agoHelpfull: Yes(1) No(0)
• x+5=2x
  x=5 before 5 years ..but now 5+5=10+ x
  10+x=10+5=15
• 9 years agoHelpfull: Yes(1) No(0)
• b) 15 years
  
  father : son
  3x : x ---->now
  
  (3x + 5) : (x + 5) ------>5 yrs after
  
  (3x + 5) = 2.5 (x + 5) ---->(father is 2.5 times the age of his son)
  x = 15
  
  Son's age = 15 years
• 9 years agoHelpfull: Yes(0) No(0)