the total wages of apiece of work if done by A & B together(in equal proportion) areRs 17300. A can do 80% of this work in 64 days and B can do 70% of the same work in 59.5 days. the wage rate of A is 110% of that of B. A can be employed for a maximum of 70% of the work and b for 60% of the work. the min cost fro getting the work done would be?

• Rs 17000
  
  A can do 80% work in 64 days
  
  80% --- 64
  100% --- x
  
  x = 100*64/80 = 80 days
  ie A the finish the work in 80 days
  
  B can do 70% work in 59.5 days
  
  70% --- 59.5
  100% --- x
  
  x = 100*59.5/70 = 85 days
  ie B the finish the work in 85 days
  
  Given work done by A and B together in equal proportion. So half of the work is done by A and the other half by B.
  So
  A takes 40 days(80/2 days) to do half of the work
  and
  B takes 42.5 days(85/2 days).
  
  Let the wage rate of B be x
  wage rate of A = 110% of B's wage rate
  = 110/100*x
  = 1.1x
  
  Total wage = 17300
  Wage = number of days worked*wage rate
  17300 = 40*1.1x + 42.5*x
  17300 = 86.5x
  x = 200
  
  ie, wage rate of B = Rs 200/day
  wage rate of A = Rs 220/day
  
  For minimum cost, the work is done by B alone.
  
  Minimum cost for getting the work done = 200*85
  =Rs 17000
  
• 10 years agoHelpfull: Yes(1) No(1)