A boxing ring in the shape of a square, 20 ft on each side. How far apart would the boxers be when they are in opposite corners of the ring?

• 28.28 ft.
  distance between the boxers=length of hypotenuse of right angled triangle with side 20 ft.
  =Sqrt(20^2+20^2)=Sqrt(800)=20*Sqrt(2)=28.28
• 10 years agoHelpfull: Yes(0) No(0)