Q1) Find two consecutive integers such that the sum of the first and the square of the second is 19

Q2) Find 3 consecutive integers such that the square of the first, decreased by 5 times the second is 9

• 1) 3,4
  If two consecutive integers are x & x+1
  Given x+(x+1)^2=19, x^2+3x-18=0, (x-3)(x+6)=0, x=3, So x+1=4
  
  
  2)7,8,9
  If three consecutive integers are x, x+1 & x+2
  Given x^2-5(x+1)=9, x^2-5x-14=0
  (x+2)(x-7)=0, x=7, So x+1=8, x+2=9
• 10 years agoHelpfull: Yes(1) No(0)