Q1) The Square of the sum of 2 consecutive integers is 49. Find the integers.

Q2) One Number is 11 more than another. If the product of the two numbers is -24, find the Numbers.

• 1) 3,4
  If two consecutive integers are x & x+1
  Given, (x+x+1)^2=49, x^2+x-12=0, (x-3)(x+4)=0, x=3, so x+1=4
  
  
  2)8, -3 or -8, 3
  If two numbers are x & y,
  Given, y=11+x ---(i) &
  x*y=-24 ---(ii)
  Substituting value of x=y-11 from (i) into (ii)
  (y-11)y=-24 or y^2-11y+24=0
  (y-8)(y-3)=0, y=8 or 3 So x=y-11=-3 or -8
• 10 years agoHelpfull: Yes(1) No(0)