x^2-3x-3=0

• Use the quadratic formula .
  
  a² + bx + c = 0
  x² - 3x - 3 = 0
  a = 1, b = -3, c = -3
  x = [-b ± √(b² - 4ac)] / 2a
  x = [3 ±√((-3)² - 4(1)(-3)] / 2(1)
  x = [3 ± √(9 + 12)] / 2
  x = [3 ± √21] / 2
  x ≈ (3 - √21) / 2 OR x ≈ (3 + √21) / 2
  x ≈ -0.79 OR x ≈ 3.79
  x ≈ -0.79, 3.79
• 10 years agoHelpfull: Yes(0) No(0)